A right pyramid has a square base of side 6 cm and a perpendicular height of 4 cm. What is its total surface area, in cm2?
The slant height is not given and is not the same as the height. Get it from the right triangle on the apothem first, then everything else follows.
1 apothem = 6 / 2 = 3
2 l = √(32 + 42) = 5
3 4 triangles = 4 × ½ × 6 × 5 = 60
4 base = 36, total = 96
84 is what you get if you use 4 as the slant height instead of the perpendicular height. It is the single most common way to lose this question.
3, 4, 5 is the first triple to test whenever a pyramid gives you an even base and a whole height. You should not be reaching for Pythagoras here.